4c^2-(9(4c-9))=0

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Solution for 4c^2-(9(4c-9))=0 equation: 



4c^2-(9(4c-9))=0



We calculate terms in parentheses: -(9(4c-9)), so:

9(4c-9)

We multiply parentheses

36c-81

Back to the equation:

-(36c-81)



We get rid of parentheses

4c^2-36c+81=0

a = 4; b = -36; c = +81;
Δ = b2-4ac
Δ = -362-4·4·81
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$c=\frac{-b}{2a}=\frac{36}{8}=4+1/2$

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